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...Lecture surface area integrals in the previous we dened a s of parametric by r u v on t double integral rr k kdudv wewill now drive formula for graph function suppose is given z f x y that example unit hemisphere p where liesinthecircular region then can be considered as xi yj this case becomes q dxdy because i j let us nd portion sphere lies inside cylinder ax note union two graphs will use to evaluate fx fy and projection xy plane see figure symmetry acos ardrd remark since kr sin cos written eg fdudv e g compute torus bcos bsin b are constants such form with parameters either or do not have know how looks like however understanding rv implies hence therefore d ab problem also solved using pappus theorem l dene concept called scalar functions surfaces used center mass moment inertia occur several applications get course them continuous bounded over denoted gd dudv provided rhs exists if letsbethehemisphericalsurfacez werst parameterize follows asin simplecalculation shows equation le...