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...Areas by integration area under a curve region bounded the given function vertical lines and x axis horizontal y between curves defined two functions if f is continuous nonnegative of on closed interval then graph b dx when calculating follow steps below sketch determine boundaries set up definite integral integrate ex find in first quadrant xand to intercepts or so therefore andb www rit edu asc page xx solve xis equal square units following finding implies from we see that our boundary at value solution equation above but it not bounding here s why an important tool help us correct results don t skip this step other line are certain problems easier rewrite terms calculate using elements case formula for would be d g dy c...